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#### bg2m8o

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Amazing - Check this out
Suppose you have two variables, a and b, both of them nonzero and such that:
a=b
Multiply both sides of the equation by a and you will have:
a2= ab
Subtract b2 from both sides of the equation to obtain:
a2-b2=ab-b2
Factoring both sides of the equation results in:
(a+b)(a-b)=b(a-b)
Divide both sides fo the equation by(a-b) to obtain:
a+b=b
Since we started with the fact that a=b, we can substitute a by b, thus:
b+b=b
It easily follows that 2b=b, thus, dividing both sides by b results n
2=1

I can now tell my employees that that make twice as much as they thought!!!!!

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Nerd

#### GTO JUDGE

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Amazing - Check this out
Suppose you have two variables, a and b, both of them nonzero and such that:
a=b
Multiply both sides of the equation by a and you will have:
a2= ab
Subtract b2 from both sides of the equation to obtain:
a2-b2=ab-b2
Factoring both sides of the equation results in:
(a+b)(a-b)=b(a-b)
Divide both sides fo the equation by(a-b) to obtain:
a+b=b
Since we started with the fact that a=b, we can substitute a by b, thus:
b+b=b
It easily follows that 2b=b, thus, dividing both sides by b results n
2=1

I can now tell my employees that that make twice as much as they thought!!!!!
3-Stooges..... Reminds me of when they were census takers and were taking census of football players as they were at the line of scrimmage.... or when they were professors.... B-A-B.....B-A-B....B-I bickie BI, bay boy boo, Bickie bay boy boo bickie a .... bickie BA-BOY-BOO.... and so on....:willy: :willy: :willy: :willy:

#### bg2m8o

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3-Stooges..... Reminds me of when they were census takers and were taking census of football players as they were at the line of scrimmage.... or when they were professors.... B-A-B.....B-A-B....B-I bickie BI, bay boy boo, Bickie bay boy boo bickie a .... bickie BA-BOY-BOO.... and so on....:willy: :willy: :willy: :willy:
Big stooge fan. But you know, the funniest sketch of ALL TIME still has to be Abbott and Costellos "Who's on First" It is simply beyond comedic genius! No one can nor likely ever will top that. I crack up everyime I hear it like it was the first. Amazing.

#### bg2m8o

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Your not being nice now! I am NOT a NERD, NO NO NO.

OK, I am............

#### TR GTO

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234 Posts
I'm a nerd, but unfortunately my nerd abilities aren't strong with math.

#### BobG

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Amazing - Check this out
Suppose you have two variables, a and b, both of them nonzero and such that:
a=b
Multiply both sides of the equation by a and you will have:
a2= ab
Subtract b2 from both sides of the equation to obtain:
a2-b2=ab-b2
Actually, at this point, you have zero equals zero, and zero cannot be factored.

Factoring both sides of the equation results in:
(a+b)(a-b)=b(a-b)
Divide both sides fo the equation by(a-b) to obtain:
a+b=b
Since we started with the fact that a=b, we can substitute a by b, thus:
b+b=b
It easily follows that 2b=b, thus, dividing both sides by b results n
2=1

I can now tell my employees that that make twice as much as they thought!!!!!

Although it is correct by the rules of math that I can do anything I want to an equation, as long as I do it to both sides equally, I cannot simply ignore other laws of math, such as zero divided by any value is indeterminate, and any value divided by zero is undefined.

my 3.14159265358 cents ...

#### TR GTO

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"ZOOOOOOOOM" (Everything going way over my head)

#### pickinfights

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Your not being nice now! I am NOT a NERD, NO NO NO.

OK, I am............
Duh, Dungeon masters don't have levels.

#### bg2m8o

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Actually, at this point, you have zero equals zero, and zero cannot be factored.

Although it is correct by the rules of math that I can do anything I want to an equation, as long as I do it to both sides equally, I cannot simply ignore other laws of math, such as zero divided by any value is indeterminate, and any value divided by zero is undefined.

my 3.14159265358 cents ...

Nice - You're absolutely correct. I would also think that technically, the agrument was over at a=b

Nerd count = 2!

#### Sabraxas

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Actually, at this point, you have zero equals zero, and zero cannot be factored.

Although it is correct by the rules of math that I can do anything I want to an equation, as long as I do it to both sides equally, I cannot simply ignore other laws of math, such as zero divided by any value is indeterminate, and any value divided by zero is undefined.

my 3.14159265358 cents ...
mmmmmmmm. I like Pi

#### 242379

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276 Posts
Amazing - Check this out
Suppose you have two variables, a and b, both of them nonzero and such that:
a=b
Multiply both sides of the equation by a and you will have:
a2= ab
Subtract b2 from both sides of the equation to obtain:
a2-b2=ab-b2
Factoring both sides of the equation results in:
(a+b)(a-b)=b(a-b)
Divide both sides fo the equation by(a-b) to obtain:
a+b=b
Since we started with the fact that a=b, we can substitute a by b, thus:
b+b=b
It easily follows that 2b=b, thus, dividing both sides by b results n
2=1

I can now tell my employees that that make twice as much as they thought!!!!!
From the employee side 2=1 means we're only getting paid half of what we should!
:agree

Time to strikearty:
:cheers

#### Joey R

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...duh... I like boobies....:willy:

#### sniper.x611

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151 Posts
Amazing - Check this out
Suppose you have two variables, a and b, both of them nonzero and such that:
a=b
Multiply both sides of the equation by a and you will have:
a2= ab
Subtract b2 from both sides of the equation to obtain:
a2-b2=ab-b2
Factoring both sides of the equation results in:
(a+b)(a-b)=b(a-b)
Divide both sides fo the equation by(a-b) to obtain:
a+b=b
Since we started with the fact that a=b, we can substitute a by b, thus:
b+b=b
It easily follows that 2b=b, thus, dividing both sides by b results n
2=1

I can now tell my employees that that make twice as much as they thought!!!!!
Actually this proof does work... as long as they are variables, they are undefined and equal. i.e. we can't assume a=b other than at the beginning... That makes no sense to anyone huh?

{
nerd_points += points;
}

#### bg2m8o

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4 nerds so far.

Guess what fellow nerds - I've got another. You wanted I can maybe be posting to this wery same tread!

#### sniper.x611

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sure, just don't make it too nerdy, I don't like it when I get excited and my glasses fog up....

#### BobG

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Actually this proof does work... as long as they are variables, they are undefined and equal. i.e. we can't assume a=b other than at the beginning... That makes no sense to anyone huh?